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सिद्ध कीजिये - `int_(0)^(pi//2)log(sinx)dx=int_(0)^(pi//2)log(cosx)dx=(pi)/(2)log((1)/(2))` |
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Answer» `int_(0)^(pi//2)log tan x dx= int_(0)^(pi//2)(log sin x - log cos x)dx` `=int_(0)^(pi//2)log sin ((pi)/(2)-x)dx-int_(0)^(pi//2)log(cosx)dx` |
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