InterviewSolution
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सिद्ध कीजिये - `int_(0)^(pi//2)log tan x dx =0` |
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Answer» `I=int_(0)^(pi)(x)/(1+cos^(2)x)dx=int_(0)^(pi)((pi-x))/(1+cos^(2)x(pi-x))dx=int_(0)^(pi)((pi-x))/(1+cos^(2)x)dx` `rArr" "2I=pi int_(0)^(pi)(dx)/(1+cos^(2)x)=2pi int_(0)^(pi//2)(sec^(2)x)/(sec^(2)x+1)dx` `=2pi int_(0)^(pi//2)(sec^(2)x)/(2+tan^(2)x)dx` अब माना `" "tan x=t` |
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