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Signal to quantization noise ratio of a PCM encoder is given by _________(a) 6.02n + α(b) 3n + 6.02α(c) n + 6.02α(d) 6.02n + αI got this question by my college director while I was bunking the class.Origin of the question is Quantization Techniques in chapter Speech Coding of Wireless/Mobile

Answer» CORRECT option is (d) 6.02n + α

Easiest explanation: Signal to quantization noise (SQNR) ratio of a PCM ENCODER is related to the number of BITS, n used for encoding. It follows the following RELATION, SQNR= 6.02n + α. Here, α = 4.77 dB for peak SQNR and α = 0 dB for average SQNR.


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