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Simplify each of the following:`cos^(-1)(3/5cosx+4/5sinx)`, where `-(3pi)/4lt=xlt=pi/4` |
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Answer» `cos^-1 (3/5 cos x + 4/5 sin x)` here, `cos alpha= 3/5` `sin alpha = 4/5` so,`cos^-1[cos alpha cos x + sin alpha sin x]` `= cos^-1[ cos(x- alpha)]` `x- alpha` as`alpha = cos^-1 (3/5) = sin^-1(4/5) = tan^-1(4/3)` so,answer=`x- tan^-1 (4/3)` |
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