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Sin (1+tan)+ cos(1+cot)=sec+cosec

Answer» According to given sum,sin (1+tan)+cos (1+cot)=sec+cosec\xa0=> LHS= sin (1+tan)+cos (1+1/tan)=> sin (1+tan)+cos (1+tan)/tan=> (1+tan)(sin+cos/tan)=> (1+tan)(sin.tan+cos)/tan=> (1+tan)(sin2/cos+cos)/tan=> (1+tan)(sin2+cos2)/tan.cos=>(1+tan)/tan.cos=>(1/tan.cos)+tan/tan.cos=>( cot/cos)+(1/cos)=> cosec +secLHS= RHS.


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