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| 1. |
(Sin^3A+cos^3A/sinA+cosA) + sinAcosA |
| Answer» {tex}\\begin{array}{l}\\frac{\\sin\\;^3A\\;+\\cos^3A}{\\sin A+\\cos A}+\\;\\sin AcosA\\\\={\\textstyle\\frac{\\textstyle(\\sin A\\;+\\;\\cos A)(\\sin^2A+\\cos^2A-\\sin A\\cos A)}{\\sin{\\textstyle A}{\\textstyle\\;}{\\textstyle+}{\\textstyle\\cos}{\\textstyle A}}}\\;+\\;\\sin AcosA\\\\=\\sin^2A+\\cos^2A-\\sin A\\cos A+\\;\\sin AcosA\\\\=1\\\\\\end{array}{/tex} | |