Sin 3A. Cos(A-26). Where 3A andA-26 are acute angle

1.	Sin 3A. Cos(A-26). Where 3A andA-26 are acute angle
Answer» We know that,Sin(90-theta) =cos thetaSo,cos(90-3A) can be compared to cos(90-A-26)90-3A=64-A90-64=-A+3A26=2AA=13°from here onwards u can find the value of 3A and vice versa

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