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Sin(45+A)-cos(45-A) is equal to 0.....how? |
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Answer» It was so simple.thank you guys Sin(45+A)-cos(45-A)=sin(90-(45+A))-cos(45-A)=cos(45-A)-cos(45-A)=0 sin(45° + A) - cos(45° - A)= sin(45° + A) - sin[90° - (45° - A)]= sin(45° + A) - sin(90° - 45° + A)= sin(45° + A) - sin(45° + A)= 0. ?hmm... |
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