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| 1. |
sin 45.sin30+cos 45.cos30= |
| Answer» \xa0We know that Sin30°={tex}\\frac12{/tex}, Sin45°= {tex}\\frac{1}{\\sqrt2}{/tex} = Cos45°, Cos30°={tex}\\frac{\\sqrt{3}}{2}{/tex} ,putting these values in given expression, we get :-{tex}\\sin 45^\\circ \\sin 30^\\circ + \\cos 45^\\circ \\cos 30^\\circ {/tex}{tex} = \\frac{1}{{\\sqrt 2 }} \\times \\frac{1}{2} + \\frac{1}{{\\sqrt 2 }} \\times \\frac{{\\sqrt 3 }}{2}{/tex}{tex} = \\frac{1}{{2\\sqrt 2 }} + \\frac{{\\sqrt 3 }}{{2\\sqrt 2 }}{/tex}{tex} = \\frac{{1 + \\sqrt 3 }}{{2\\sqrt 2 }}{/tex} | |