Sin^4x/a+cos^4x/b=1/a+1/b to prove that sin^8x /a^3+cosx^8/b^3=1/[a+b]

1.	Sin^4x/a+cos^4x/b=1/a+1/b to prove that sin^8x /a^3+cosx^8/b^3=1/[a+b]^3
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