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Sin(6O°+ θ)-Cos(30°- θ)=? |
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Answer» 1 0 Ans 0 Cos (30° - θ) = cos { 90° -(60° + θ)}= sin(60°+ θ)Now, Sin(60° + θ) - cos(30° - θ)= Sin(60° + θ) - sin(60°+ θ)= 0 |
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