sin (75°) =__________________(a) (1 – \(\sqrt{3}\))/2\(\sqrt{2}\)(b) (\(\sqrt{3}\) + 1)/2\(\sqrt{2}\)(c) (\(\sqrt{3}\) – 1)/2\(\sqrt{2}\)(d) (- \(\sqrt{3}\) – 1)/2\(\sqrt{2}\)I got this question during an online interview.My question comes from Trigonometric Functions of Sum and Difference of Two Angles-1 topic in chapter Trigonometric Functions of Mathematics – Class 11

sin (75°) =__________________(a) (1 – \(\sqrt{3}\))/2\(\sqrt{2}\)(b

1.	sin (75°) =__________________(a) (1 – \(\sqrt{3}\))/2\(\sqrt{2}\)(b) (\(\sqrt{3}\) + 1)/2\(\sqrt{2}\)(c) (\(\sqrt{3}\) – 1)/2\(\sqrt{2}\)(d) (- \(\sqrt{3}\) – 1)/2\(\sqrt{2}\)I got this question during an online interview.My question comes from Trigonometric Functions of Sum and Difference of Two Angles-1 topic in chapter Trigonometric Functions of Mathematics – Class 11
Answer» The CORRECT OPTION is (B) (\(\sqrt{3}\) + 1)/2\(\sqrt{2}\) The explanation: sin (75°) = sin (45°+30°) = sin45° cos30° + cos45° sin30° = (1/\(\sqrt{2}\) * \(\sqrt{3}\)/2) + (1/\(\sqrt{2}\) * 1/2) {sin(X + y)=sin x cos y + cos x sin y} = (\(\sqrt{3}\) + 1)/2\(\sqrt{2}\).

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