sin 75° + sin 15° = _________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}\)(b) \(\frac{\sqrt{2}}{\sqrt{3}}\)(c) \(\frac{\sqrt{3}}{2}\)(d) \(\frac{1}{\sqrt{2}}\)This question was addressed to me by my school principal while I was bunking the class.My doubt stems from Trigonometric Functions of Sum and Difference of Two Angles-2 in section Trigonometric Functions of Mathematics – Class 11

sin 75° + sin 15° = _________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}

1.	sin 75° + sin 15° = _________________(a) \(\frac{\sqrt{3}}{\sqrt{2}}\)(b) \(\frac{\sqrt{2}}{\sqrt{3}}\)(c) \(\frac{\sqrt{3}}{2}\)(d) \(\frac{1}{\sqrt{2}}\)This question was addressed to me by my school principal while I was bunking the class.My doubt stems from Trigonometric Functions of Sum and Difference of Two Angles-2 in section Trigonometric Functions of Mathematics – Class 11
Answer» Right choice is (a) \(\FRAC{\SQRT{3}}{\sqrt{2}}\) For explanation I would SAY: We KNOW, sin x + sin y = 2 sin (x+y)/2 cos (x-y)/2 sin 75° + sin 15° = 2 sin (75°+15°)/2cos(75°-15°)/2 = 2 sin 45° cos 30° = 21/\(\sqrt{2}\)\(\sqrt{3}\)/2 = \(\sqrt{3}\)/\(\sqrt{2}\).

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