sin A-2sin³A\\2cos³ A-cos A=tan A

1.	sin A-2sin³A\\2cos³ A-cos A=tan A
Answer» LHS:sinA(1-2sin^2)/cosA(2cos^2-1) = sinA(sin^2A+cos^2A-2sin^2A) \\cosA(2cos^2A-(sin^2A+cos^2A) =sinA(cos^2A-sin^2A)/cosA(cos^2A-sin^2A) =sinA/cosA =tanA =RHS Hence proved

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