Sin(b+c)/2*cosA/2+cos(b+c)/2*Sina/2

1.	Sin(b+c)/2cosA/2+cos(b+c)/2Sina/2
Answer» We knoe that A+B+C=180 B+C=180-A (B+C)/2=(180-A)/2 (B+C)/2=90-A/2 Cos(B+C)/2=Cos(90-A/2) Cos(B+C)/2=Sin A/2Or, Sin(B+C)/2=Sin(90-A/2) Sin(B+C)/2=Cos A/2Now, According to questionSin(b+c)/2 * cos A/2 +cos(b+c)/2 sin A/2Cos A/2 cos A/2 + sinA/2 *sin A/2 Cos^2 A/2+sin^ A/2 1 is ur answer

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