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| 1. |
Sin theta + cos theta=√2 then evaluate tantheta + cot theta |
| Answer» SinA+cos A=√2 Squaring both sides to getSin^2A +cos^2A +2sinAcosA=21+2sinAcosA=2We get,Sin AcosA=1/2Now tanA+cotA=sin A/cosA+cosA/sinA=1/sinAcosAPutting the value tanA+cotA=2 | |