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Sin18°/cos72° evaluate this. |
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Answer» Sin 18/cos72 cos(90-72)/cos72Cos72/sin72=1Tan26/tan(90-74)=1Cos48-sin42=sin(90-42)-sin42=0Cosec31-Cosec(90-69) Cose31-Cosec31=0 Sin theata = cos (90 - theata) So, Sin 18° =cos (90°- 18°) =cos 72° Cos 72°/cos72° =1 |
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