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| 1. |
(sin²Acos²B-cos²Asin²B) =(sin²A-sin²B) |
| Answer» [sin²A(1-sin²B)-(1-sin²A)sin²B][sin²A-sin²Asin²B-(sin²B-sin²Asin²B)](sin²A-sin²Asin²B-sin²B+sin²Asin²B)(sin²A-sin²B) | |