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| 1. |
Sin6A+cos6A=1-3sin2Acos2A |
| Answer» a n s w e r\xa0sin^6A + cos^6A= (sin^2A)3 + (cos^2A)3= (sin^2 A + cos^2 A) (sin^4 A – sin^2A cos^2A + cos^4A)= 1 (sin^4A – sin^2Acos^2A + cos^4A + 2sin^2Acos^2A – 2sin^2Acos^2A)= (sin2A + cos2A) – 3sin2A cos2A= 1 – 3sin^2Acos^2A | |