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| 1. |
(sina+cosa)^2=1+2sina×cosa |
| Answer» By using identity (a+b)^2= a^2 + b^2 + 2ab Therefore,LHS, = (SinA +CosA)^2= Sin^2A + Cos^2A + 2SinACosA= 1 + 2SinACosA [ Sin^2 + Cos^2A =1]PROVED | |