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| 1. |
SinA+cosA=√2cosA ,prove that cosA-sinA=√2sinA |
| Answer» SinA+cosA=√2cosASinA=√2cosA-cosASinA=(√2-1)cosASinA=(√2-1÷1×√2+1÷√2+1)×cosASinA=(2-1÷√2+1)×cosASinA=cosA÷√2+1(√2-1)×sinA=cosA√2sinA+sinA=cosA√2sinA=cosA-sinA | |