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(SinA+CosA)(TanA+CotA)=secA+cosecA

Answer» (1/cosecA+1/secA)(sinA/cosA+cosA/sinA)=(secA+cosecA/secA×cosecA)×(sin^2A+cos^2A/cosA×sinA)=(secA+cosecA/secA×cosecA )× (1×cosecA×secA/1)=secA+cosecA,(hence proved).


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