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| 1. |
(sinA÷secA+tanA-1)+(cosA÷cosecA+cotA-1) |
| Answer» Take the first term ...and split it =>SinA/secA + sinA/tanA - sinA =>SinAcosA + cosA - sinA In the same way split the second term...it will result in cosAsinA + sinA - cosAAdd both...=>After elimination there will be left only ( sinAcosA )^2 Change cos A as 1/sinA SinA will be cancelled out and ( 1 ) ^2= 1Hence proved!! | |