InterviewSolution
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संमाकलनो का मान ज्ञात कीजिएः। `int_(4)^(9) (sqrtx)/((30-x^(3//2))^(2))d x` |
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Answer» यहाँ `underset(4)overset(9)int (sqrtx)/((3-x^(3//2))^(2))dx` माना `30-x^(3//2)=t rArr -3/2sqrtx dx=dt` और `x=9 rArr 30=(9)^(3//2)=39-27=3` `therefore I=2/3 underset(22)overset(3)int =-2/3underset(22)overset(3)int t^(-2)dt` `=-2/3.[(-1)/(t)]_(22)^(3)=-2/3[-1/3+1/22]` `=-2/3 xx (-19)/(66)=(19)/99` |
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