Solution for 9x²+14x-8 using completing square method

1.	Solution for 9x²+14x-8 using completing square method
Answer» Solution for 9x^2-14x-8=0 equation:Simplifying9x2 + -14x + -8 = 0Reorder the terms:-8 + -14x + 9x2 = 0Solving-8 + -14x + 9x2 = 0Solving for variable \'x\'.Factor a trinomial.(-4 + -9x)(2 + -1x) = 0Subproblem 1Set the factor \'(-4 + -9x)\' equal to zero and attempt to solve:Simplifying-4 + -9x = 0Solving-4 + -9x = 0Move all terms containing x to the left, all other terms to the right.Add \'4\' to each side of the equation.-4 + 4 + -9x = 0 + 4Combine like terms: -4 + 4 = 00 + -9x = 0 + 4-9x = 0 + 4Combine like terms: 0 + 4 = 4-9x = 4Divide each side by \'-9\'.x = -0.4444444444Simplifyingx = -0.4444444444Subproblem 2Set the factor \'(2 + -1x)\' equal to zero and attempt to solve:Simplifying2 + -1x = 0Solving2 + -1x = 0Move all terms containing x to the left, all other terms to the right.Add \'-2\' to each side of the equation.2 + -2 + -1x = 0 + -2Combine like terms: 2 + -2 = 00 + -1x = 0 + -2-1x = 0 + -2Combine like terms: 0 + -2 = -2-1x = -2Divide each side by \'-1\'.x = 2Simplifyingx = 2Solutionx = {-0.4444444444, 2}

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