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Solve : `2sin^(2)theta=(1)/(2),0^(@)ltthetalt90^(@)`. |
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Answer» `2sin^(2)theta=(1)/(2)` `rArrsin^(2)theta=(1)/(2xx2)=(1)/(4)` `rArrsintheta=sqrt((1)/(4))=(1)/(2)` (taking positive sign only) `rArrsinthetasin30^(@)` `rArrtheta=30^(@)` |
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