1.

Solve : `2sin^(2)theta=(1)/(2),0^(@)ltthetalt90^(@)`.

Answer» `2sin^(2)theta=(1)/(2)`
`rArrsin^(2)theta=(1)/(2xx2)=(1)/(4)`
`rArrsintheta=sqrt((1)/(4))=(1)/(2)` (taking positive sign only)
`rArrsinthetasin30^(@)`
`rArrtheta=30^(@)`


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