Solve 2x+3y=11 and 2x-4y=-24 and hence find the value of m for which y

1.	Solve 2x+3y=11 and 2x-4y=-24 and hence find the value of m for which y=mx+3 .
Answer» Hi Fbgne Hi yogita thanks for your solution I have miscalculated the value of x and m By using elimination method we can easily get y=5, x=1/3, m=6 Given equations are\xa02x+3y=11−−−−(1)2x−4y=−24−−−−(2)Form (1)2x+3y=11\xa0⇒2x=11−3y⇒x=211−3y\u200b−−−(3)substituting x in(2)2x−4y=−24\xa0⇒2(211−3y\u200b)−4y=−24⇒11−3y−4y=−24⇒11−7y=−24⇒7y=35⇒y=35/7⇒y=5.putting y = 5 in (3)\xa0x=[11−3(5)\u200b]/2⇒x=[11−15\u200b]/2⇒x=−4/2∴x=−2.Hence x = -2 and y = 5 is the solution of the\xa0equation.Now, we have to find my=mx+3 ∴m=−15=3(−2)+35−3=−2m⇒−2m=2⇒m=−2/x=−1

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