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Solve \(4\dfrac{2}{3}+ 3\dfrac{1}{2}-1\dfrac{2}{3}=?\)1. \(2\dfrac{1}{5}\)2. \(2\dfrac{5}{3}\)3. \(1\dfrac{3}{4}\)4. \(6\dfrac{1}{2}\) |
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Answer» Correct Answer - Option 4 : \(6\dfrac{1}{2}\) Calculation: ⇒ \(4\dfrac{2}{3}+ 3\dfrac{1}{2}-1\dfrac{2}{3}\) ⇒ \(\dfrac{14}{3}+ \dfrac{7}{2}-\dfrac{5}{3}\) ⇒ \(\dfrac{28 + 21 - 10}{6}\) ⇒ \(\dfrac{49 - 10}{6}\) ⇒ \(\dfrac{39}{6}\) = \(\dfrac{13}{2}\) = \(6\dfrac{1}{2}\) ∴ Solution for \(4\dfrac{2}{3}+ 3\dfrac{1}{2}-1\dfrac{2}{3}\) is \(6\dfrac{1}{2}\).
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