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Solve:`4^(log_2 x)-2x-3=0` |
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Answer» `4^(log_2x) - 2x- 3 = 0` `=>2^(2(log_2x)) - 2x - 3 = 0` `=>2^(log_2x^2) -2x -3 = 0` `=>x^2-2x-3 = 0` (As `a^(log_ab) = b`) `=>x^2 - 3x+x-3 = 0` `=>x(x-3)+1(x-3) = 0` `=>(x-3)(x+1) = 0` `x=3 and x =-1` But, `x` can not be negative, So, `x = 3` |
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