Solve: 4x^2 - 4ax+ (a^2-b^2) = 0

1.	Solve: 4x^2 - 4ax+ (a^2-b^2) = 0
Answer» But my answer is right Ok. No problem! Sorry j my answer has a mistake.so my answer is wrong 4x²-4ax+(a²-b²) 4x²-4ax+(a+b)(a-b)=0m²-n² =(m+n)(m-n) Splitting the middle term, we get=> 4x² -2(a+b)x-2(a-b)x +(a+b)(a-b)=0=> 2x[2x-(a+b)]-(a-b)[2x-(a+b)]=0=> [2x-(a+b)][2x-(a-b)]=0=> 2x-(a+b)=0 Or 2x-(a-b)=0=> 2x = a+b Or 2x = a-b Then x=a+b/2,x=a-b/2 4x²-2(a+b)x-2(a-b)x+(a²-b²) => 2x{x-(a+b)}-2(a-b){x-(a+b)} => (2x-2a+2b)(x-a-b) => x=a--b or a+b

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