Saved Bookmarks
| 1. |
Solve 4x^2 + 4bx-(a^2-b^2)=0 |
| Answer» We have the following equation,4x2 + 4bx - (a2 - b2) = 0Now,4x2 + 4bx - (a2 - b2) = 0{tex}\\Rightarrow{/tex}\xa04x2 - 2(a - b)x + 2(a + b)x - (a2 - b2) = 0{tex}\\Rightarrow{/tex} 2x[2x - (a - b)] + (a + b)[2x - (a - b)] = 0{tex}\\Rightarrow{/tex} [2x - (a - b)] [2x + (a + b)] = 0{tex}\\Rightarrow{/tex} 2x - (a - b) = 0 or 2x + (a + b) = 0{tex}\\Rightarrow{/tex}\xa02x = a - b or 2x = -a - b{tex} \\Rightarrow x = \\frac{{a - b}}{2}{/tex} or {tex}x = \\frac{{ - a - b}}{2}{/tex} | |