Saved Bookmarks
| 1. |
Solve 4x2-2(a2+b2)x+a2b2=0 find the value of x\xa0 |
| Answer» a= 4b= -2(a2+b2)c= a2b2Using Discriminant formula,D= b2-4ac[-2(a2+b2)]2-4 x4xa2b24(a4+b4+2a2b2)-16a2b2(2a2-2b2)2\xa0x=\xa0(-b±D)/\xa02ax= [2(a2+b2)+2(a2-b2)]/8 = 4a2/8 = a2/2x= [2(a2+b2)-2(a2-b2)]/8 = 4b2/8 = b2/2 | |