1.

Solve by factorization method:-9x^2-9(a+b)x+(2a^2+5ab+2b^2)=0

Answer» 9x^2-9 (a+b)x+(2a^2+5ab+2b^2)=0= 9x^2-3(a+2b)x-3(2a+b)x+(a+2b)(2a+b)=0= 3x[3x-(a+2b)]-(2a+b)[3x-(a+2b)]=0= x= a+2b/3 and x= 2a+b/3


Discussion

No Comment Found