InterviewSolution
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InterviewSolution
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Solve by substitution method3x-y=39x-3y=9Plz solve this ?????? |
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Answer» 3x-y=3........19x-3y=9..(divided by 3)3x-y=3......23x=3-yX=3-y/3sub X in 13x-y=33(3-y/3)-y=33-y-y=3-2y=3-3y=0sub y in 23x-y=33x-0=33x=3X=1 3x-y=3........(i)9x-3y=9..(divided by 3)3x-y=3......(i)3x=3-yX=3-y/3sub X in (i)3x-y=33(3-y/3)-y=33-y-y=3-2y=3-3y=0sub y in (ii)3x-y=33x-0=33x=3X=1 Put the value,Y=3x-3 in eq (2) 9x-3(3x-3)=9 => 9x-9x+9=9.. hence, proved |
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