Solve, exercise 5.1,Q.4,(xii)

1.	Solve, exercise 5.1,Q.4,(xii)
Answer» Thanks (xii) √2, √8, √18, √32\xa0…Here,a2\xa0–\xa0a1\xa0= √8-√2 = 2√2-√2\xa0= √2a3\xa0–\xa0a2\xa0= √18-√8\xa0= 3√2-2√2\xa0= √2a4\xa0–\xa0a3\xa0= 4√2-3√2\xa0= √2Since,\xa0an+1\xa0–\xa0an\xa0or the common difference is same every time.Therefore,\xa0d\xa0=\xa0√2\xa0and the given series forms a A.P.Hence, next three terms are;a5\xa0= √32+√2\xa0= 4√2+√2\xa0= 5√2\xa0= √50a6\xa0= 5√2+√2\xa0= 6√2\xa0= √72a7\xa0= 6√2+√2\xa0= 7√2\xa0= √98

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