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solve for x 36x^2-12ax+(a^2-b^2)=0 |
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Answer» 36x2−12ax+(a2−b2)=0Ax2+Bx+C=0\xa0from,A=36 B=−12a C=(a2−b2)Roots of quadratic equation formula :x=2A−B±B2−4AC\u200b\u200b=2×3612a±144a2−144(a2−b2)\u200b\u200b=7212a±144b2\u200b\u200b=7212a±12b\u200b=6a±b\u200b⇒x=6a+b\u200b\xa0or\xa06a−b\u200b pls reply |
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