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| 1. |
Solve for X;4x^2-2 (a^2+b^2)x+a^2b^2=0 |
| Answer» {tex}4{x^2} - 2\\left( {{a^2} + {b^2}} \\right)x + {a^2}{b^2} = 0{/tex}=> {tex}4{x^2} - 2{a^2}x - 2{b^2}x + {a^2}{b^2} = 0{/tex}=> {tex}2x\\left( {2x - {a^2}} \\right) - {b^2}\\left( {2x - {a^2}} \\right) = 0{/tex}=> {tex}\\left( {2x - {a^2}} \\right)\\left( {2x - {b^2}} \\right) = 0{/tex}=> {tex}2x - {a^2} = 0{/tex}\xa0and {tex}2x - {b^2} = 0{/tex}=> {tex}x = {{{a^2}} \\over 2}{/tex}\xa0and {tex}x = {{{b^2}} \\over 2}{/tex} | |