InterviewSolution
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InterviewSolution
| 1. |
Solve for x=9x2-6ax+(a2+b2) |
| Answer» Given equation, 9x2- 6ax + a2- b2 = 0{tex}\\therefore \\quad x = \\frac { 6 a \\pm \\sqrt { ( - 6 a ) ^ { 2 } - 4 \\times 9 \\times \\left( a ^ { 2 } - b ^ { 2 } \\right) } } { 2 \\times 9 }{/tex}or,\xa0{tex}x = \\frac { 6 a \\pm \\sqrt { 36 a ^ { 2 } - 36 a ^ { 2 } + 36 b ^ { 2 } } } { 18 }{/tex}or,{tex}x = \\frac { 6 a + 6 b } { 18 } , x = \\frac { 6 a - 6 b } { 18 }{/tex}or,\xa0{tex}x = \\frac { 6 ( a + b ) } { 18 } , x = \\frac { 6 ( a - b ) } { 18 }{/tex}or,\xa0{tex}x = \\frac { a + b } { 3 } , x = \\frac { a - b } { 3 }{/tex} | |