Solve for \'x\' and \'y\'7(y+3)-2(x+2)=144(y-2)+3(x-3)=2

1.	Solve for \'x\' and \'y\'7(y+3)-2(x+2)=144(y-2)+3(x-3)=2
Answer» The given equations are:7(y + 3) - 2(x + 2) = 144(y - 2) + 3(x - 3) = 2So, 7(y + 3) - 2(x + 2) = 14⇒ 7y + 21 - 2x - 4 = 14⇒ 7y - 2x = 14 + 4 - 21⇒ - 2x + 7y = -3 ........ (i)And 4(y - 2) + 3(x - 3) = 2⇒ 4y - x + 3x - 9 = 2⇒ 4y + 3x = 2 + 8 + 9⇒ 3x + 4y = 19 .............(ii)Multiplying (i) by 4 and (ii) by 7, we get-8x + 28y = -12........(iii)21x + 28y = 133......(iv)Subtracting (iii) and (iv),we get29x = 145x = 5Substituting x = 5 in (i),we get7y = -3 + 10⇒ 7y = 7⇒ y = 1{tex}\\therefore{/tex}\xa0Solution is x = 5, y = 1

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