solve graphically the systen of linear equations4x-3y+4=04x+3y-20=0

1.	solve graphically the systen of linear equations4x-3y+4=04x+3y-20=0
Answer» 4x−3y+4=0⟹x=4−4+3y\u200bLet,\xa0y=4, then\xa0x=4−4+3(4)\u200b=2Similarly, when\xa0y=0,x=−14x+3y−20=0⟹x=420−3y\u200bLet,\xa0y=4, then\xa0x=420−3(4)\u200b=2Similarly, when\xa0y=0,x=5Plotting the above points on the graph, we get, the intersecting point i.e(2,4)Area of the region bounded by these lines and x-axis\xa0=21\u200b×6units×4\xa0units=12\xa0sq.\xa0units.Hope you understand.......

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