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Solve : `log_(3)x . log_(4)x.log_(5)x=log_(3)x.log_(4)x+log_(4)x.log_(5)+log_(5)x.log_(3)x`. |
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Answer» Correct Answer - 60 `log_(3)x.log_(4)x.log_(5)x=log_(3)x.log_(4)x+log_(4)x.log_(5)x+log_(5)x.log_(3)x.` Let `log_(x)3=p, log_(x)4=q, log_(x)5=4` `rArr (1)/(pqr)=(1)/(pq)+(1)/(qr)=(1)/(pr)` `rArr p+q+r=1` `rArr log_(x)3+log_(x)4+log_(x)5=1` `rArr log_(x)60=1` `rArr x = 60` |
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