Solve p^2x^2+(p^2-q^2)x-q^2

1.	Solve p^2x^2+(p^2-q^2)x-q^2
Answer» \xa0p^2x^2+(p^2-q^2)x-q^2=0\xa0p^2x^2+p^2x-q^2x-q^2=0p^2x(x+1)-q^2(x+1)=0(x+1)(p^2x-q^2)=0x+1=0 so x=-1p^2x-q^2=0or x=q^2/p^2\xa0\xa0

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