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Solve pair of linear equation by substitution method1-....6x-5y=1 2x+3y=5 |
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Answer» Sorry,the value of x is (1+5y)÷6 not 3 Taking equation 16x-5y=1Here x=(1+5y)÷3Put the value of x in equation 2, 2x+3y=52[(1+5y)÷6]+3y=5(1+5y)÷3+3y=55y÷3+3y=5-1÷3(5y+9y)÷3=(15-1)÷314y=14Therefore,y=1Now,put the value of y in equation 16x-5(1)=16x-5=16x=1+56x=6Therefore,x=1The answer is X=1 and Y=1 x=1, y=1. |
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