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| 1. |
Solve the equation:22x+3=65(2x-2)+122. |
| Answer» Ans. Equation is in the Form = 22x+3\xa0\xa0= 65 (2x\xa0- 2\xa0) + 122=> 22x\xa0. 23\xa0= 65 ( 2x\xa0- 2\xa0) + 122=> 8(2x)2\xa0= 65 ( 2x\xa0- 2) + 122Put 2x\xa0= y , We get\xa0=> 8y2\xa0= 65(y-2) + 122=> 8y2 = 65y - 130 + 122=> 8y2\xa0- 65y + 8 = 0=> 8y2 - 64y - y + 8 = 0=> 8y ( y - 8) - 1(y-8) = 0=> (8y-1) ( y - 8) = 0Either 8y -1 = 0 or y - 8 = 0So, y = 1/8 or 8=> 2x\xa0= 1/8 or 2x\xa0= 8=> 2x\xa0= (2)-3 or 2x\xa0= (2)3On comparing, We get\xa0x = -3, 3 | |