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| 1. |
Solve the equation: 4+(-1)+2+............ +x =437 |
| Answer» It is an arithmetic series.a = -4, d = +3-4 - 1 + 2 + 5 + .... +\xa0(x - 3) + x = 437Sum of the series = [\xa02 a + (n-1)d ]n /2 = 437\xa0[- 8 + 3(n-1)] n / 2 = 437- 11n + 3n² = 8743 n² -11n - 874 = 0n = (11 +- 103 )/6 = 114/6 = 19 as n is positive\xa0only.So, x = a + (n-1)d = -4 + 3 (19-1) = 50 | |