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| 1. |
Solve the equation by elimination method x+y=5 and2x-3y=4 |
| Answer» x\xa0+\xa0y\xa0=5 ...\xa0(i)2x\xa0–3y\xa0= 4 ...\xa0(ii)Multiplying equation\xa0(i)\xa0by\xa02, we get2x\xa0+ 2y\xa0= 10 ...\xa0(iii)2x\xa0–3y\xa0= 4 ...\xa0(ii)Subtracting equation\xa0(ii)\xa0from equation\xa0(iii), we get5y\xa0= 6y\xa0= 6/5Putting the value in equation\xa0(i), we getx\xa0= 5 - (6/5) = 19/5Hence,\xa0x\xa0= 19/5 and\xa0y\xa0= 6/5 | |