Solve the following by substitution method x/7+y/3=5,x/2-y/9=6?

1.	Solve the following by substitution method x/7+y/3=5,x/2-y/9=6?
Answer» Thx, but mera doubt bina google ke hi clear ho gaya☺☺ Google se copy krogi to Asahi hoga Thx? {tex} Given\\:pair\\:of\\: equations:\\\\\\frac{x}{7}+\\frac{y}{3}=5{/tex}{tex}\\implies \\frac{y}{3}=5-\\frac{x}{7}\\:---(1){/tex}{tex}and\\:\\frac{x}{2}-\\frac{y}{9}=6{/tex}{tex}\\implies \\frac{x}{2}-\\frac{y}{3}\\times \\frac{1}{3}=6\\:---(2){/tex}{tex}substitute \\:(1)\\:in \\: equation\\:(2),\\: we\\:get{/tex}{tex}\\implies \\frac{x}{2}-(5-\\frac{x}{7})\\times \\frac{1}{3}=6\\:---(2){/tex}{tex}\\implies \\frac{x}{2}-\\frac{5}{3}+\\frac{x}{21}=6{/tex}{tex}\\implies \\frac{x}{2}+\\frac{x}{21}=6+\\frac{5}{3}{/tex}{tex}\\implies \\frac{21x+2x}{42}=\\frac{18+5}{3}{/tex}{tex}\\implies \\frac{23x}{42}=\\frac{21}{3}{/tex}{tex}\\implies x = \\frac{23}{3}\\times \\frac{42}{23}{/tex}{tex}\\implies x = 14\\:--(3){/tex}{tex}put \\: x=14 \\: in \\: equation \\:(1),\\\\we\\:get{/tex}{tex}\\frac{y}{3}=5-\\frac{14}{7}{/tex}{tex}\\implies \\frac{y}{3}=5-2{/tex}{tex}\\implies y = 3\\times 3 = 9{/tex}Therefore,{tex}x = 14 , \\: y = 9{/tex}\xa0

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