solve the following equation 3x-2y+3=0,4x+3y-47=0 by. cross multiplica

1.	solve the following equation 3x-2y+3=0,4x+3y-47=0 by. cross multiplication method
Answer» {tex}3x - 2y + 3 = 0{/tex}........(i){tex}4x + 3y - 47 = 0{/tex}......(ii)By cross multiplication, we have{tex}\\therefore \\frac { x } { [ ( - 2 ) \\times ( - 47 ) - ( 3 \\times 3 ) ] }{/tex}{tex}= \\frac { y } { [ ( 3 \\times 4 ) - ( - 47 ) \\times 3 ] }{/tex}{tex}= \\frac { 1 } { [ 3 \\times 3 - ( - 2 ) \\times 4 ] }{/tex}{tex}\\Rightarrow \\quad \\frac { x } { ( 94 - 9 ) } = \\frac { y } { ( 12 + 141 ) } = \\frac { 1 } { ( 9 + 8 ) }{/tex}{tex}\\Rightarrow \\quad \\frac { x } { 85 } = \\frac { 1 } { 17 } , \\frac { y } { 153 } = \\frac { 1 } { 17 }{/tex}{tex}17x = 85, \\ 17y = 153{/tex}{tex}\\Rightarrow \\quad x = \\frac { 85 } { 17 } , y = \\frac { 153 } { 17 }{/tex}Therefore, the solution is {tex}x = 5,\\ y = 9{/tex}

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