1.

Solve the following equations:`sin[2cos^(-1)"{"cot"("2tan^(-1)x"}]"=0`

Answer» `sin(2cos^(1-)(cot(2tan^(-1)x)))=0`
`2cos^(-1)(cot(2tan^(-1)x))=sin^(-1)0=0`
`cos^(-1)(cot(2tan^(-1)x))=0`
`cot(2tan^(-1)x)=cos0`
`cot(2tan^(-1)x)=1`
`cot(tan^(-1)((2x)/(1-x^2)))=1`
`(1-x^2)/(2x)=1`
`1-x^2=2x`
`x^2+2x-1=0`
`x=(-2pmsqrt(4+4))/2`
`x=-1pmsqrt2`.


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