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Solve the following equations:`sin[2cos^(-1)"{"cot"("2tan^(-1)x"}]"=0` |
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Answer» `sin(2cos^(1-)(cot(2tan^(-1)x)))=0` `2cos^(-1)(cot(2tan^(-1)x))=sin^(-1)0=0` `cos^(-1)(cot(2tan^(-1)x))=0` `cot(2tan^(-1)x)=cos0` `cot(2tan^(-1)x)=1` `cot(tan^(-1)((2x)/(1-x^2)))=1` `(1-x^2)/(2x)=1` `1-x^2=2x` `x^2+2x-1=0` `x=(-2pmsqrt(4+4))/2` `x=-1pmsqrt2`. |
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