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Solve the following pair of equations 2x+3y=46, 3x+5y=74 by elimation method

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Given pair of linear equations is2x + 3y = 46 …(i)And 3x + 5y = 74 …(ii)On multiplying Eq. (i) by 3 and Eq. (ii) by 2 to make the coefficients of x equal, we get the equation as6x + 9y = 138 …(iii)6x + 10y = 148 …(iv)On subtracting Eq. (iii) from Eq. (iv), we get6x + 10y – 6x – 9y = 148 – 138⇒\xa0y = 10On putting y = 10 in Eq. (ii), we get3x + 5y = 74⇒\xa03x + 5(10) = 74⇒\xa03x + 50 = 74⇒\xa03x = 74 – 50⇒\xa03x = 24⇒\xa0x = 8Hence, x = 8 and y = 10 , which is the required solution.


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